Laravel Paginate not working

Stefan Bogdanescu

Founder & Senior Architect · 2026-06-29

Laravel Company
# Troubleshooting Laravel Pagination: Why `$products->links()` Fails with the Query Builder As a senior developer, I frequently encounter situations where seemingly straightforward operations break down in unexpected ways. One common point of friction developers hit when dealing with data retrieval and pagination in Laravel is the difference between using Eloquent Models and raw Query Builder methods. If you are experiencing an error like "Method links does not exist" when trying to render pagination links, it usually points to a misunderstanding of what object method you are calling or how the specific query result is structured. This post will diagnose why your specific scenario occurs when using `DB::table()->paginate()` and provide the robust, idiomatic Laravel solution. --- ## The Problem Analysis: Raw Queries vs. Eloquent Pagination You presented the following code snippet: ```php public function productSearch(Request $request) { $name = $request->name; $products = DB::table('products') ->where('name', 'LIKE', "%$name%") ->paginate(4); return view('product',compact('products')); } ``` And when trying to render the links: `{{ $products->links() }}` you receive an error. ### Why this happens: When you use the Eloquent ORM (Object-Relational Mapper), methods like `paginate()` are deeply integrated with the Model structure. Laravel ensures that any object returned by an Eloquent operation is a fully functional Paginator instance, which inherently has the necessary methods (`links()`, `next()`, etc.) available for Blade rendering. However, when you use the raw Query Builder via `DB::table(...)` and chain `.paginate()`, while this *does* return a paginator object (specifically a `LengthAwarePaginator`), sometimes the context or the specific version of Laravel/database setup can cause issues when attempting to access methods directly in certain view contexts, leading to that method not being recognized by the compiler. The core issue isn't necessarily that the data isn't paginated; it’s how you are accessing the pagination metadata from the result object. ## The Best Practice Solution: Embrace Eloquent The most reliable and maintainable way to handle data retrieval, relationships, and pagination in Laravel is by utilizing Eloquent Models. Eloquent abstracts away the raw SQL details and provides a clean, consistent interface for all operations, including pagination. This approach aligns perfectly with the principles promoted by frameworks like those found at [laravelcompany.com](https://laravelcompany.com). ### Solution 1: Refactoring to Use Eloquent Instead of querying the database directly via `DB::table()`, define a corresponding Eloquent Model and use its built-in pagination methods. **Step 1: Define the Model (e.g., `Product.php`)** ```php // app/Models/Product.php namespace App\Models; use Illuminate\Database\Eloquent\Model; class Product extends Model { // ... model properties } ``` **Step 2: Refactor the Controller Method** Now, use the Eloquent `paginate()` method directly on the Model. This guarantees that the resulting object is a fully functional Paginator with all necessary links. ```php use App\Models\Product; // Make sure you import your model use Illuminate\Http\Request; public function productSearch(Request $request) { $name = $request->name; // Use the Eloquent Model for pagination $products = Product::where('name', 'LIKE', "%{$name}%") ->paginate(4); return view('product',compact('products')); } ``` With this change, when you access `$products->links()` in your Blade file, it will work flawlessly because the object is a standard Eloquent Paginator. ## Alternative Fix: Accessing Pagination Data Directly If, for some highly specific legacy reasons, you absolutely must stick with the raw Query Builder approach, remember that the paginator object *does* contain the links data. You can access the necessary components directly from the result: ```php // If you insist on using DB::table() $products = DB::table('products') ->where('name', 'LIKE', "%$name%") ->paginate(4); // Accessing links via the structure provided by the paginator object return view('product',compact('products')); // $products is still the Paginator object ``` In this case, if `$products->links()` fails, it often indicates a deeply nested issue or an incompatible environment setup. Sticking to Eloquent (as shown in Solution 1) avoids these intermittent errors entirely and provides you with cleaner, more powerful tools for data management, which is central to the philosophy of Laravel. ## Conclusion The error you encountered is a classic symptom of mixing raw database operations with ORM-specific expectations. As senior developers, our goal should always be to leverage the abstraction layers provided by the framework. By migrating your data access logic from `DB::table()` to Eloquent Models, you ensure that your pagination functionality is robust, readable, and compatible with Laravel's intended structure. Always start with Eloquent when dealing with collections and pagination; it saves debugging time and prevents these kinds of frustrating runtime errors.