Check if Object already exists in Collection - Laravel
Stefan Bogdanescu
Founder & Senior Architect · 2026-06-29
In your code, you are retrieving objects from a database query using Laravel's Eloquent ORM. The issue lies in the fact that your loop is not checking if the service object is already present within the $servicesImpacted collection before pushing it to the collection. This leads to duplicates appearing in the final collection.
Laravel's contains() method only checks for reference equality, which can lead to issues when comparing objects with unique attributes. A more suitable approach would be to use Laravel Collections to your advantage and compare object values using equal() instead of contain().
Approach 1: Using the Laravel Collections Equal Method
In this method, you can employ the Laravel Collection's \Illuminate\Support\Collection::equal() function to ensure objects with unique attributes are added only once. Here is an example code snippet:$servicesImpacted = collect([]); // An empty collection
foreach ($osRed as $os) {
foreach ($os->services as $service) {
if (!($servicesImpacted->containsUsing(function ($existingService, $service) {
return $existingService === null || $existingService->name == $service->name && $existingService->id == $service->id;
}, $service))) {
$servicesImpacted->push($service);
}
}
}Approach 2: Using Laravel Collections Unique Method
In the absence of a unique identifier (like id) in your services, you can use the Laravel Collection's \Illuminate\Support\Collection::unique() method to easily achieve this. Here is the revised code snippet:$servicesImpacted = collect(array_merge($servicesImpacted->get(), $osRed->pluck('services')->toArray())); // Combine the initial collection with new services
$servicesImpacted->unique('name'); // Remove duplicates by their 'name' attributeIn conclusion, by implementing one of these methods or a combination of both, you can effectively avoid object duplications within Laravel collections and ensure that your collections are always accurate and up-to-date with no duplicate entries.