Call to a member function links() on array in laravel
Stefan Bogdanescu
Founder & Senior Architect · 2026-06-29
Demystifying the Error: Why You Get "Call to a member function links() on array" with Laravel Pagination
As a senior developer working with the Laravel framework, we frequently encounter seemingly cryptic errors when dealing with data retrieval and presentation. One of the most common pitfalls developers face when implementing pagination is the error: Call to a member function links() on array. This error usually points to a fundamental misunderstanding of what object you are trying to call methods on.
This post will dive deep into why this error occurs when working with Laravel's pagination system, analyze your specific code context, and provide the correct, robust solution.
Understanding the Root Cause: Paginator vs. Array
The error message is crystal clear: you are attempting to call the links() method on a variable that PHP recognizes as a simple array, not an object that possesses that method.
In Laravel, when you use methods like paginate(), Eloquent or the Query Builder automatically returns a special class instance—specifically, a LengthAwarePaginator (or similar paginator classes). This object is designed to handle the complex logic of determining page numbers, total counts, and generating the necessary HTML links for navigation.
The problem arises when you manipulate this object in a way that strips away its structure.
Analyzing Your Code Scenario
Let's look at the code snippets you provided:
Controller Logic:
use Illuminate\Pagination\LengthAwarePaginator;
public function index(){
$data = DB::table('tasks')->paginate(1); // $data is a LengthAwarePaginator object
$data = json_decode(json_encode($data), true); // <-- This line destroys the Paginator object!
return view('index',['data' => $data]);
}
Blade View:
{{ $data->links() }} // <-- Error occurs here because $data is now an array.
The critical step causing the failure is: $data = json_decode(json_encode($data), true);. By encoding the paginator object into a JSON string and then decoding it back, you effectively convert the structured Paginator object into a simple PHP associative or indexed array. Arrays do not have a links() method, leading directly to the fatal error.
The Correct Approach: Handling Pagination in Blade
The correct way to handle pagination links is to pass the full paginator object directly to your view. Laravel is designed to automatically render the necessary HTML for navigation when it sees this object in the view layer.
Best Practice Implementation
Instead of manipulating the data structure before sending it to the view, let the Paginator object do its job. If you need to pass specific data to the view, extract it before or after pagination, but keep the paginator intact for link generation.
Here is how you should structure your controller and view:
Controller (Corrected):
use Illuminate\Support\Facades\DB;
public function index(){
// Return the paginator object directly
$tasks = DB::table('tasks')->paginate(1);
// Pass the entire paginator object to the view
return view('index', ['tasks' => $tasks]);
}
Blade File (Corrected):
When you pass the $tasks object, Laravel knows how to render it. You access the links method directly on the paginator:
{{ $tasks->links() }}
This approach ensures that the links() method is called on the correct type of object (LengthAwarePaginator), resolving the error and adhering to best practices for data flow in Laravel applications, as advocated by resources like https://laravelcompany.com.
Advanced Context: When to Use JSON Encoding
While the above solution fixes your immediate error, it's important to understand when you do use json_encode() and json_decode(). This technique is primarily used when preparing data for an API response. If you are building a RESTful endpoint, you should return the paginator object directly (Laravel handles serializing it automatically via controllers) or manually transform it into a standard JSON structure using Laravel's Resource classes.
For simple view rendering where navigation links are required, retaining the Paginator object is always the superior path over converting it to a raw array.
Conclusion
The error Call to a member function links() on array is a classic indicator that you have inadvertently destroyed a necessary object structure by performing data transformations too early. By understanding the distinction between a Laravel Paginator object and a standard PHP array, we can write cleaner, more predictable code. Always prioritize passing the appropriate Eloquent/Paginator objects to your Blade views to leverage Laravel's built-in features for rendering pagination seamlessly.